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24.01-69.6x+49x^2=0
a = 49; b = -69.6; c = +24.01;
Δ = b2-4ac
Δ = -69.62-4·49·24.01
Δ = 138.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69.6)-\sqrt{138.2}}{2*49}=\frac{69.6-\sqrt{138.2}}{98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69.6)+\sqrt{138.2}}{2*49}=\frac{69.6+\sqrt{138.2}}{98} $
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